Building Blocks
Sunday, April 7, 2013
Test^2
Consider, $$ \begin{equation}\label{eq:gravt} F=G\frac{mM}{r^2} \end{equation} $$ and, $$ \begin{equation}\label{eq:gravo} F=mg \end{equation} $$ Combining ($ \ref{eq:gravt} $) and ($ \ref{eq:gravo} $) yield, $$ g=G\frac{M}{r^2} $$
1 comment:
Angel Agüero
April 7, 2015 at 2:11 AM
$$\pi = \int_{0}^{1} \frac{4}{1+x^{2}}$$
Reply
Delete
Replies
Reply
Add comment
Load more...
Newer Post
Home
Subscribe to:
Post Comments (Atom)

$$\pi = \int_{0}^{1} \frac{4}{1+x^{2}}$$

ReplyDelete